It sounds a lot like a multinomial. I posted this in another thread, but it may have been missed. I'm not sure how you calculate the Brewers winning probabilities by team so I will give you an example using a six sided die. First of all the multinomial pdf is as straight forward to calculate as a binomial and it looks like this for a random vector (X1....Xn): f(x1..xn) = m! / (x1!*x2!.......*xn!) * p1^x1 * p2^x2 .......*pn^xn Alright, back to the example. Suppose the die is unbalanced so that the probability of observing a 1 is 1/21, a 2 is 2/21, and so on. (X1, X2, X3, X4, X5, X6) is a random vector that counts the number of times that number comes up in 10 tosses of the die. m=10 trials, n=6 possible outcomes, p1=1/21......p6=6/21. What's the probability that in 10 rolls I get four 6's, three 5's, two 4's, and one 3? 10! / (0!0!1!2!3!4!) * (1/21)^0 * (2/21)^0 * (3/21)^1 * (4/21)^2 * (5/21)^3 * (6/21)^4 = .0059 So back to baseball and out of the world of colored balls, urns, flips of coins and rolls of die. I would have to think about it some more, but I believe you could treat each opponent as a random variable and the remainder of the season as the number of trials. This is where simulation is handy. You would have to think of all possible outcomes (2 of 3 from Chicago), (2 of 6 from Houston), etc. However, based on your probabilities and plugging the function above you could run through most combinations. (Do you have access to sas, S+, R or any other statistics package? You could whip through this stuff in seconds)