Edit: After looking at it again, did I understand the situation correctly? Does the chart mean the "CS" is the guy going from 1st to 2nd, the guy going from 3rd to home, or both? I would think it's any "CS" event occurring in that situation, so both. I suspect that most are the 1st to 2nd variety. You should be able to check those numbers using this: http://www.tangotiger.net/RE9902.html 1.243 (1 & 2,1 out) - .387 (3, 2 out) = .856 (compared to the .95 of the previous table). Probably a few of those CS were the 3-H variety, which would be more costly? EDIT: From checking the chart rluz shared, the safe SB was a .38, but a CS there would have been a -.60. Nearly double the value, but in the negative direction! Yikes. Boy am I glad Hall was safe. Really, in that case, RE is pretty inconsequential. You only need 1 run. You are better off looking this: http://www.tangotiger.net/RE9902score.html Runner on 2B with 1 out scores at least 1 run 41% of the time. Runner on 3B with 1 out scores at least 1 run 66% of the time. No runner and 2 out scores at least 1 run 8% of the time. Turn that into win%: Chance of winning before SB: 71% (50% + .5 x 42%) Chance of winning after SB: 83% (50% + .5 x 66%) Chance of winning after CS: 54% (50% + .5 x 8%) That agrees with the actual results pretty well: http://winexp.walkoffbalk.com/expectancy/search/?start_year=1977&end_year=2006&team=H&inning=9&outs=1&expectancy[bases]=2&scorediff=0 A SB adds 12% to the win%, a CS subtracts 29%. If I'm doing to right, a CS is 2.4 times more costly than a SB is beneficial. You better be darn certain your SB attempt is going to succeed in that situation.